3x^2-62x-220=0

Solution for 3x^2-62x-220=0 equation:

3x^2-62x-220=0

a = 3; b = -62; c = -220;
Δ = b2-4ac
Δ = -622-4·3·(-220)
Δ = 6484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{6484}=\sqrt{4*1621}=\sqrt{4}*\sqrt{1621}=2\sqrt{1621}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-62)-2\sqrt{1621}}{2*3}=\frac{62-2\sqrt{1621}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-62)+2\sqrt{1621}}{2*3}=\frac{62+2\sqrt{1621}}{6}
$